WEBVTT

1
00:00:00.000 --> 00:00:07.419
Here is the problem: A 10 kg cart accelerates at 2.5 m/s squared. What net force acts on it?

2
00:00:07.869 --> 00:00:13.906
Use the Newton prime s second law formula, rearranged for the unknown, in SI units.

3
00:00:14.706 --> 00:00:17.527
Formula: Newton prime s second law.

4
00:00:17.977 --> 00:00:19.939
Substitute the known values.

5
00:00:20.739 --> 00:00:24.559
So the answer is net force F equals 25 N.

6
00:00:25.009 --> 00:00:41.507
Newton prime s second law links the net force on an object to its acceleration: F equals ma. Force and acceleration point the same way, so a negative force gives a negative acceleration. One newton accelerates one kilogram by 1 m/s squared.

7
00:00:42.307 --> 00:00:47.752
Substituted every value back into the formula: both sides agree, which checks out.
