WEBVTT

1
00:00:00.000 --> 00:00:08.429
Here is the problem: A 90 N force pulls a box 10 m at 37° to the direction of motion. How much work does it do?

2
00:00:08.879 --> 00:00:14.858
Use the work done by a constant force formula, rearranged for the unknown, in SI units.

3
00:00:15.658 --> 00:00:18.630
Formula: work done by a constant force.

4
00:00:19.080 --> 00:00:21.019
Substitute the known values.

5
00:00:21.819 --> 00:00:27.949
So the answer is work W equals 718.772 J.

6
00:00:28.399 --> 00:00:42.285
Only the component of the force along the displacement does work, hence the cos theta. Work is positive when the force has a component along the motion, negative when it opposes it (theta greater than 90°), and zero when it is perpendicular.

7
00:00:43.084 --> 00:00:48.726
Substituted every value back into the formula: both sides agree, which checks out.
