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Here is the problem: A right triangle has legs 1 and 1. Find the hypotenuse.

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Find the hypotenuse of a right triangle from its two legs.

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Write the Pythagorean theorem. The hypotenuse c is the side opposite the right angle and is always the longest side.

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Substitute the legs and square them.

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Take the positive square root. Lengths are positive, so only the positive root is used.

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Area and perimeter.

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Acute angles. Angle A is opposite leg a and angle B is opposite leg b; the right angle C is 90°.

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So the answer is c equals the square root of 2 approximately 1.414213562; area equals 1 over 2 approximately 0.5; perimeter approximately 3.414213562; angles approximately 45°, 45°, 90°.

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In every right triangle the square on the hypotenuse equals the sum of the squares on the two legs. Knowing any two sides fixes the third, and the angles follow from the tangent ratio.

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Check: a squared plus b squared equals 2 and c squared equals 2, which agree.

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Angle sum: 90° plus 45° plus 45° equals 180°.