WEBVTT

1
00:00:00.000 --> 00:00:05.480
Here is the problem: A right triangle has legs 6 and 8. Find the hypotenuse.

2
00:00:05.930 --> 00:00:09.483
Find the hypotenuse of a right triangle from its two legs.

3
00:00:10.283 --> 00:00:17.946
Write the Pythagorean theorem. The hypotenuse c is the side opposite the right angle and is always the longest side.

4
00:00:18.396 --> 00:00:20.486
Substitute the legs and square them.

5
00:00:20.936 --> 00:00:26.370
Take the positive square root. Lengths are positive, so only the positive root is used.

6
00:00:26.820 --> 00:00:28.167
Area and perimeter.

7
00:00:28.967 --> 00:00:36.966
Acute angles. Angle A is opposite leg a and angle B is opposite leg b; the right angle C is 90°.

8
00:00:37.766 --> 00:00:54.856
So the answer is c equals 10; area equals 24; perimeter approximately 24; angles approximately 36.869898°, 53.130102°, 90°.

9
00:00:55.306 --> 00:01:06.974
In every right triangle the square on the hypotenuse equals the sum of the squares on the two legs. Knowing any two sides fixes the third, and the angles follow from the tangent ratio.

10
00:01:07.774 --> 00:01:14.276
Check: a squared plus b squared equals 100 and c squared equals 100, which agree.

11
00:01:14.726 --> 00:01:20.322
(6, 8, 10) is a Pythagorean triple: all three sides are whole numbers.

12
00:01:20.772 --> 00:01:33.624
Angle sum: 90° plus 36.869898° plus 53.130102° equals 180°.
