WEBVTT

1
00:00:00.000 --> 00:00:07.814
Here is the problem: An event has 1 favorable outcomes out of 6 equally likely outcomes. What is its probability?

2
00:00:08.264 --> 00:00:11.027
Single event (favorable divided by total).

3
00:00:11.827 --> 00:00:15.658
Divide favorable outcomes by total equally likely outcomes.

4
00:00:16.108 --> 00:00:18.372
Complement: the event does not happen.

5
00:00:18.822 --> 00:00:19.960
Odds in favor.

6
00:00:20.760 --> 00:00:30.594
So the answer is P(A) equals 1 over 6 approximately 0.16666667 (16.666667 percent).

7
00:00:31.044 --> 00:00:45.104
The event occurs in 1 of 6 equally likely outcomes, so its probability is 16.666667 percent; it fails with probability 83.333333 percent.
