WEBVTT

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Here is the problem: k times A: A equals [[1, 2], [3, 4]].

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Compute k times A exactly.

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Read matrix A.

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Multiply every entry by k equals 2.

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Result.

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So the answer is k times A equals [[2, 4], [6, 8]].

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A scalar multiple scales every entry by the same number.

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All arithmetic is exact (fractions, no rounding).