WEBVTT

1
00:00:00.000 --> 00:00:04.528
Here is the problem: Evaluate log base 2 of 1 over 32.

2
00:00:04.978 --> 00:00:08.658
Evaluate the logarithm of 1 over 32 with base 2.

3
00:00:09.458 --> 00:00:12.198
Ask: what power of the base gives the number?

4
00:00:12.648 --> 00:00:22.563
Write both numbers as powers of the same prime factors. Comparing prime exponents shows 1 over 32 equals 2 to the power negative 5.

5
00:00:23.363 --> 00:00:28.111
So the answer is log 2(1 over 32) equals negative 5.

6
00:00:28.562 --> 00:00:32.800
2 raised to negative 5 gives 1 over 32 exactly.

7
00:00:33.600 --> 00:00:39.347
Check: 2 to the power negative 5 approximately 0.03125.
