WEBVTT

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Here is the problem: (3x minus 5) squared minus (3x plus 6).

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Expand and simplify the polynomial into standard form.

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Distribute every product and power. Multiply each term of one factor by each term of the other; expand powers by repeated multiplication.

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Combine like terms and order by degree.

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Read off the key features. degree 2, leading coefficient 9, constant term 19.

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So the answer is 9x squared minus 33x plus 19.

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In standard form the polynomial is 9x squared minus 33x plus 19 (degree 2, leading coefficient 9, constant term 19).

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Spot check at x equals 2: original and expanded form both give negative 11.