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Here is the problem: d by d x((x squared minus 1) cubed (x plus 2)).

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Find the derivative of ((x squared minus 1) cubed (x plus 2)) with respect to x.

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Product rule: (uv) prime equals u prime v plus uv prime.

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Sum rule: differentiate each term separately.

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Power rule with the chain rule: d by d x[u to the power n] equals n times u to the power n minus 1 times u prime.

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Difference rule: differentiate each term separately.

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Power rule: d by d x[x to the power n] equals n times x to the power n minus 1.

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Combine and simplify.

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So the answer is f prime of x equals 6(x squared minus 1) squaredx(x plus 2) plus (x squared minus 1) cubed.

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The derivative is built from the outside in: sums split into terms, constants factor out, products and quotients use their rules, and every composite function multiplies by the derivative of its inside (chain rule).

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Cross-checked numerically against an independent symbolic differentiator at 8 sample points, which checks out.