WEBVTT

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Here is the problem: Find the distance between (negative 2, 1) and (3, negative 3).

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Find the straight-line (Euclidean) distance between two points in the plane.

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Label the points.

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Find the horizontal and vertical differences.

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Square the differences and add them.

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Take the square root.

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Midpoint (average of the coordinates).

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So the answer is d equals the square root of 41 approximately 6.4031242.

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The distance formula is the Pythagorean theorem applied to the right triangle whose legs are the horizontal and vertical differences between the points.

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d squared equals 41 matches deltax squared plus deltay squared equals 41.