WEBVTT

1
00:00:00.000 --> 00:00:05.619
Here is the problem: Find the distance between (negative 5, 0) and (0, 5).

2
00:00:06.069 --> 00:00:10.237
Find the straight-line (Euclidean) distance between two points in the plane.

3
00:00:11.037 --> 00:00:12.152
Label the points.

4
00:00:12.602 --> 00:00:15.295
Find the horizontal and vertical differences.

5
00:00:15.745 --> 00:00:17.695
Square the differences and add them.

6
00:00:18.146 --> 00:00:19.458
Take the square root.

7
00:00:20.258 --> 00:00:22.290
Midpoint (average of the coordinates).

8
00:00:23.090 --> 00:00:31.496
So the answer is d equals 5the square root of 2 approximately 7.0710678.

9
00:00:31.946 --> 00:00:40.665
The distance formula is the Pythagorean theorem applied to the right triangle whose legs are the horizontal and vertical differences between the points.

10
00:00:41.465 --> 00:00:47.374
d squared equals 50 matches deltax squared plus deltay squared equals 50.