WEBVTT

1
00:00:00.000 --> 00:00:06.908
Here is the problem: Find the population standard deviation of 1, 3, 5, 7, 9.

2
00:00:07.358 --> 00:00:11.305
Treat the data as the entire population (divide by n).

3
00:00:12.105 --> 00:00:12.964
Find the mean.

4
00:00:13.414 --> 00:00:15.759
Square each deviation from the mean.

5
00:00:16.209 --> 00:00:18.055
Add the squared deviations.

6
00:00:18.505 --> 00:00:21.849
Divide by n to get the population variance.

7
00:00:22.649 --> 00:00:23.891
Take the square root.

8
00:00:24.691 --> 00:00:30.728
So the answer is σ equals 2.828427125.

9
00:00:31.178 --> 00:00:38.713
Standard deviation measures how spread out the values are around the mean. A small value means the data are clustered near the mean.

10
00:00:39.513 --> 00:00:47.269
Variance equals 8, and 2.828427125 squared equals 8.

11
00:00:47.718 --> 00:00:53.697
Sample SD for comparison: 3.16227766.
