WEBVTT

1
00:00:00.000 --> 00:00:08.870
Here is the problem: Find the population standard deviation of 3.2, 4.1, 2.8, 5.0.

2
00:00:09.320 --> 00:00:13.349
Treat the data as the entire population (divide by n).

3
00:00:14.149 --> 00:00:15.020
Find the mean.

4
00:00:15.470 --> 00:00:17.815
Square each deviation from the mean.

5
00:00:18.265 --> 00:00:20.146
Add the squared deviations.

6
00:00:20.596 --> 00:00:23.893
Divide by n to get the population variance.

7
00:00:24.693 --> 00:00:25.912
Take the square root.

8
00:00:26.712 --> 00:00:33.190
So the answer is σ equals 0.8496322734.

9
00:00:33.640 --> 00:00:41.256
Standard deviation measures how spread out the values are around the mean. A small value means the data are clustered near the mean.

10
00:00:42.056 --> 00:00:55.222
Variance equals 0.721875, and 0.8496322734 squared equals 0.721875.

11
00:00:55.672 --> 00:01:02.650
Sample SD for comparison: 0.9810708435.
