WEBVTT

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Here is the problem: How many moles are in 25 g of CaCO3?

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Add the atomic weights of all 5 atoms in one formula unit of CaCO3.

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Count the atoms of each element. Subscripts multiply everything inside the brackets before them, and a hydrate coefficient multiplies the whole water (or other) unit.

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Look up each atomic weight (g/mol). IUPAC standard atomic weights (abridged, conventional values).

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Multiply each count by its atomic weight.

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Add the contributions.

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Mass percent of each element.

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Convert the sample mass to moles.

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Number of formula units.

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So the answer is M(CaCO3) equals 100.086 g/mol; 25 g equals 0.249785 mol.

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The molar mass is the mass of one mole of formula units. It equals the sum of the atomic weights of every atom in the formula, and numerically matches the formula mass in daltons (u).

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Percent composition adds to 100.00 percent.

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Elements: calcium times 1, carbon times 1, oxygen times 3.