WEBVTT

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Here is the problem: How many ways can you arrange 3 of 8 items in order?

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Permutations nPr (order matters).

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Use the permutation formula.

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Cancel 5! to leave the first 3 factors of 8!

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So the answer is P(8, 3) equals 336.

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There are 336 ordered arrangements of 3 items chosen from 8.

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Check: P(8, 3) equals C(8, 3) times 3! equals 56 times 6 equals 336.