WEBVTT

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Here is the problem: How many ways can you choose 3 items from 10?

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Combinations nCr (order does not matter).

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Use the combination formula.

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Divide the permutations by r! because order does not matter.

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So the answer is C(10, 3) equals 120.

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There are 120 ways to choose 3 items from 10 when order does not matter.

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Check: P(10, 3) equals C(10, 3) times 3! equals 120 times 6 equals 720.