WEBVTT

1
00:00:00.000 --> 00:00:07.721
Here is the problem: Data: 2, 4, 4, 4, 5, 5, 7, 9.

2
00:00:08.171 --> 00:00:11.085
Measures of central tendency for a list of numbers.

3
00:00:11.885 --> 00:00:14.880
Sort the data from smallest to largest.

4
00:00:15.330 --> 00:00:18.987
Mean: add the values and divide by how many there are.

5
00:00:19.437 --> 00:00:27.436
Median: the middle value of the sorted list. With 8 values (even), the median is the average of values 4 and 5.

6
00:00:27.886 --> 00:00:31.926
Mode: the value(s) that appear most often. Most frequent: 4.

7
00:00:32.726 --> 00:00:35.408
Range: largest minus smallest.

8
00:00:36.208 --> 00:00:44.405
So the answer is Mean equals 5; Median equals 4.5; Mode equals 4; Range equals 7.

9
00:00:44.855 --> 00:00:54.828
The mean balances all values, the median splits the sorted data in half and is less affected by outliers, and the mode is the most common value.

10
00:00:55.628 --> 00:01:00.632
Sum 40 equals mean times n equals 5 times 8 equals 40.