WEBVTT

1
00:00:00.000 --> 00:00:09.892
Here is the problem: Resistors of 4, 12, 6 Ω are connected in parallel across 24 V. Find the equivalent resistance and total current.

2
00:00:10.342 --> 00:00:16.495
Resistors in parallel share the same voltage; their conductances (1/R) add.

3
00:00:17.295 --> 00:00:19.524
Parallel: reciprocals add.

4
00:00:19.974 --> 00:00:22.017
Total current from Ohm prime s law.

5
00:00:22.467 --> 00:00:27.192
Current in each branch (same voltage). The branch currents add up to the total current.

6
00:00:27.642 --> 00:00:28.698
Power delivered.

7
00:00:29.499 --> 00:00:37.208
So the answer is R T equals 2 Ω; I equals 12 A, P equals 288 W.

8
00:00:37.658 --> 00:00:46.087
The equivalent resistance of a parallel network is always smaller than its smallest resistor; two equal resistors in parallel give half of one.

9
00:00:46.887 --> 00:00:51.554
R T less than or equal to every individual resistor, which checks out.