WEBVTT

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Here is the problem: 1/(x minus 1) equals 2.

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A linear equation in x: isolate x using inverse operations.

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Start with the equation.

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Multiply both sides by x minus 1 to clear the fractions. This is only valid where x minus 1 not equal to 0, so any value that makes it zero is excluded at the end.

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Isolate x.

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So the answer is x equals 3 over 2 approximately 1.5.

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Doing the same operation to both sides keeps the equation balanced. Undoing addition, then multiplication, leaves x alone.

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x equals 1.5: left side equals 2, right side equals 2, which checks out.