WEBVTT

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Here is the problem: 6x squared plus 23x minus 34 equals 0.

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A quadratic equation in x: solve with the quadratic formula.

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Start with the equation.

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Move every term to one side to get standard form.

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Compute the discriminant.

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delta greater than 0, so there are two distinct real roots.

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Apply the quadratic formula.

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Simplify the square root.

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Reduce the fraction.

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So the answer is x equals (negative 23 minus the square root of 1345 over 12 approximately negative 4.9728535 or x equals (negative 23 plus the square root of 1345 over 12 approximately 1.1395201.

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The quadratic formula gives every solution of ax squared plus bx plus c equals 0.

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x equals negative 4.9728535: left side equals 0, right side equals 0, which checks out.

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x equals 1.1395201: left side equals 0, right side equals 0, which checks out.