WEBVTT

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Here is the problem: Solve the triangle with A equals 40°, B equals 60° and c equals 10.

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Side a is opposite angle A, b opposite B and c opposite C. This is the ASA case.

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Third angle from the angle sum.

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Remaining sides from the law of sines.

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Area and perimeter.

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So the answer is a equals 6.527036447, b equals 8.793852416, c equals 10; A equals 40°, B equals 60°, C equals 80°; area equals 28.26289687, perimeter equals 25.32088886.

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Three measurements including a side normally fix a triangle. Two sides with a non-included angle (SSA) can give zero, one or two triangles.

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Triangle 1: angles sum to 180°; a/sin A equals 10.15426612 equals c/sin C equals 10.15426612.