WEBVTT

1
00:00:00.000 --> 00:00:07.407
Here is the problem: Solve the triangle with A equals 50°, B equals 50° and c equals 8.

2
00:00:07.857 --> 00:00:14.405
Side a is opposite angle A, b opposite B and c opposite C. This is the ASA case.

3
00:00:15.205 --> 00:00:17.144
Third angle from the angle sum.

4
00:00:17.594 --> 00:00:20.171
Remaining sides from the law of sines.

5
00:00:20.621 --> 00:00:21.921
Area and perimeter.

6
00:00:22.721 --> 00:00:51.398
So the answer is a equals 6.222895307, b equals 6.222895307, c equals 8; A equals 50°, B equals 50°, C equals 80°; area equals 19.06805748, perimeter equals 20.44579061.

7
00:00:51.848 --> 00:01:00.497
Three measurements including a side normally fix a triangle. Two sides with a non-included angle (SSA) can give zero, one or two triangles.

8
00:01:01.297 --> 00:01:16.831
Triangle 1: angles sum to 180°; a/sin A equals 8.123412895 equals c/sin C equals 8.123412895.