WEBVTT

1
00:00:00.000 --> 00:00:06.176
Here is the problem: Transpose Aᵀ: A equals [[1, 2, 3], [4, 5, 6]].

2
00:00:06.627 --> 00:00:09.831
Compute Transpose Aᵀ exactly.

3
00:00:10.631 --> 00:00:11.931
Read matrix A.

4
00:00:12.381 --> 00:00:13.821
Rows become columns.

5
00:00:14.271 --> 00:00:14.910
Result.

6
00:00:15.709 --> 00:00:21.003
So the answer is Transpose Aᵀ equals [[1, 4], [2, 5], [3, 6]].

7
00:00:21.453 --> 00:00:25.238
The transpose of a 2 times 3 matrix is 3 times 2.

8
00:00:26.038 --> 00:00:29.312
All arithmetic is exact (fractions, no rounding).