WEBVTT

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Here is the problem: X is binomial with n equals 10 and p equals 0.5. Find P(X greater than or equal to 8).

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Binomial: k successes in n trials.

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Binomial probability of exactly j successes.

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Add the terms for j equals 8 to 10.

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Mean and standard deviation of the distribution.

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So the answer is P(X greater than or equal to 8) approximately 0.0546875 (5.46875 percent).

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With 10 independent trials and success probability 1 over 2 per trial, the requested probability is about 5.46875 percent.

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All binomial probabilities for j equals 0..10 add to 1.
