WEBVTT

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Here is the problem: X is binomial with n equals 12 and p equals 0.6. Find P(X greater than 9).

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Binomial: k successes in n trials.

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Binomial probability of exactly j successes.

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Add the terms for j equals 10 to 12.

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Mean and standard deviation of the distribution.

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So the answer is P(X greater than 9) approximately 0.08344332288 (8.3443323 percent).

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With 12 independent trials and success probability 3 over 5 per trial, the requested probability is about 8.34433 percent.

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All binomial probabilities for j equals 0..12 add to 1.