WEBVTT

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Here is the problem: X is binomial with n equals 8 and p equals 0.25. Find P(X less than or equal to 1).

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Binomial: k successes in n trials.

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Binomial probability of exactly j successes.

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Add the terms for j equals 0 to 1.

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Mean and standard deviation of the distribution.

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So the answer is P(X less than or equal to 1) approximately 0.3670806885 (36.708069 percent).

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With 8 independent trials and success probability 1 over 4 per trial, the requested probability is about 36.7081 percent.

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All binomial probabilities for j equals 0..8 add to 1.
