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Differential EquationsCollege3 topic explainers

Differential Equations course

Analytic solution methods for the most common ordinary differential equations.

Topics in this course

  1. 1.Separable Equations

    A differential equation relates a function to its derivatives. It is separable when it can be written dydx=g(x)h(y)\frac{dy}{dx} = g(x)h(y), so that all the yy terms can be moved to one side and all the xx terms to the other: dyh(y)=g(x) dx\frac{dy}{h(y)} = g(x)\,dx. Integrating both sides then gives the solution, with one constant of integration.

    • Divide by h(y)h(y) only where h(y)≠0h(y) \ne 0; constant solutions h(y)=0h(y) = 0 may need to be added back.
    • One constant CC is enough after integrating both sides.
    • Solve for yy explicitly when possible, then apply the initial condition.
    Quick check: For y=3ex2y = 3e^{x^2}, find y(1)y(1) to two decimals.

    8.158.15

    Includes a worked example, 3 common mistakes and 3 practice questions with answers. Study separable equations

  2. 2.Linear First-Order Equations

    A first-order linear differential equation has the form dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x). Unlike separable equations, the variables cannot generally be split, but an integrating factor μ(x)=e∫P(x) dx\mu(x) = e^{\int P(x)\,dx} makes the left side the derivative of a product, ddx(μy)\frac{d}{dx}(\mu y).

    • Write the equation in standard form, with coefficient 1 on dydx\frac{dy}{dx}, before finding μ\mu.
    • μ=e∫P dx\mu = e^{\int P\,dx}; no constant is needed in this integral.
    • After multiplying, the left side is always (μy)′(\mu y)'.
    Quick check: For y=2−2e−2xy = 2 - 2e^{-2x}, what value does yy approach as x→∞x \to \infty?

    22

    Includes a worked example, 3 common mistakes and 3 practice questions with answers. Study linear first-order equations

  3. 3.Second-Order Linear (Constant Coefficients)

    A second-order linear equation with constant coefficients, ay′′+by′+cy=0ay'' + by' + cy = 0, describes springs, pendulums and electrical circuits. Trying y=erxy = e^{rx} turns it into the characteristic equation ar2+br+c=0ar^2 + br + c = 0, an ordinary quadratic whose roots determine the shape of every solution.

    • Characteristic equation: replace y′′y'' with r2r^2, y′y' with rr, yy with 1.
    • Real distinct roots: y=C1er1x+C2er2xy = C_1 e^{r_1 x} + C_2 e^{r_2 x}.
    • Complex roots produce sines and cosines; negative real part means damping.
    Quick check: What is the sum of the roots of the characteristic equation of y′′+4y′+3y=0y'' + 4y' + 3y = 0?

    −4-4

    Includes a worked example, 3 common mistakes and 3 practice questions with answers. Study second-order linear (constant coefficients)

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