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EasyIntegralsCalculus

Evaluate ∫132x dx\int_1^3 2x\,dx.

Antiderivative x squared, evaluated at the bounds.

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Final answer

∫132x dx=8\int_{1}^{3} 2x\,dx = 8

How we read your problem

Evaluate the definite integral of 2 x from x = 1 to x = 3.

∫132x dx\int_{1}^{3} 2x\,dx

Step-by-step solution

  1. Start with the definite integral

    ∫132x dx\int_{1}^{3} 2x\,dx
  2. Power rule: ∫ xⁿ dx = xⁿ⁺¹/(n+1)

    ∫x dx=x22\int x\,dx = \frac{{x}^{2}}{2}
  3. Constant multiple rule: ∫ k·f dx = k∫ f dx

    ∫2x dx=x2\int 2x\,dx = {x}^{2}
  4. Antiderivative

    F(x)=x2F(x) = {x}^{2}
  5. Apply the fundamental theorem of calculus

    F(3)−F(1)=9−1=8F(3) - F(1) = 9 - 1 = 8

Formulas used

  • Power rule

    ∫xn dx=xn+1n+1+C, n≠−1\int x^n\,dx = \frac{x^{n+1}}{n+1} + C,\ n \neq -1
  • Fundamental theorem of calculus

    ∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a)

A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.

Verification

  • Differentiated the antiderivative and compared it with the integrand ✓
  • Adaptive Simpson's rule gives 8 ✓

About integrals

Antiderivatives, substitution and the Fundamental Theorem.

Fundamental Theorem of Calculus

A definite integral equals the change in any antiderivative.

∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx = F(b) - F(a)

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