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Word problemsArithmeticMiddle schoolabout 1:24

A $80 jacket is on sale for 30% off. What is the sale price?: animated lesson

A narrated, step-by-step word problems video lesson with captions. Final answer: New price = 56 (the discount is 24).

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.5 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Worked example
    A 80 jacket is on sale for 30% off. What is the sale price?
  2. 2. Steps, part 1
    1. Read the problem
    2. Identify the known values
    3. new=old×(1+p100)\text{new} = \text{old}\times\left(1 + \frac{p}{100}\right)
      Write the equation
    4. Solve for new
  3. 3. Steps, part 2
    1. Result
  4. 4. The answer
    New price = 56 (the discount is 24)\text{New price = 56 (the discount is 24)}

    new = 56

  5. 5. Check
    • Substituting new = 56 back into new = old × (1 + p/100) balances both sides ✓

Transcript

The problem. Here is the problem: A 80 jacket is on sale for 30 percent off. What is the sale price? The original price is 80 and it decreases by 30 percent, so the percent change is negative 30 percent. Percent increase or decrease; old equals 80, p equals negative 30 percent; solve for new.

Steps, part 1. Read the problem. The original price is 80 and it decreases by 30 percent, so the percent change is negative 30 percent. Identify the known values. Percent increase or decrease. Known: old equals 80, p equals negative 30 percent. Unknown: new value (new). Write the equation. new equals old times (1 plus p/100). Solve for new. new equals 80 times (1 plus negative 0.3).

Steps, part 2. Result. new equals 56.

The answer. So the answer is New price equals 56 (the discount is 24). Substitute the known values into new equals old times (1 plus p/100) and isolate new. Keep units consistent (for example miles, miles per hour and hours).

Check. Substituting new equals 56 back into new equals old times (1 plus p/100) balances both sides, which checks out.

About word problems

Turn everyday situations about prices, speed, ages and interest into equations and solve them.

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A $80 jacket is on sale for 30% off. What is the sale price?