A sample of 64 has mean 50; the population standard deviation is 8. Find the 90% confidence interval for the mean: animated lesson
A narrated, step-by-step confidence intervals video lesson with captions. Final answer: 90% CI: (48.3551, 51.6449); margin of error 1.64485.
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.5 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked exampleA sample of 64 has mean 50; the population standard deviation is 8. Find the 90% confidence interval for the mean.
- 2. Step by step
- Standard error of the mean
- Critical value for 90% confidence
- Margin of error
- Interval: estimate ± margin
- 3. The answer
50 ± 1.64485
- 4. Check
- The interval is centred on the estimate: (48.3551 + 51.6449) / 2 = 50.
Transcript
The problem. Here is the problem: A sample of 64 has mean 50; the population standard deviation is 8. Find the 90 percent confidence interval for the mean. Build a 90 percent confidence interval for the population mean μ.
Step by step. Standard error of the mean. Critical value for 90 percent confidence. The middle 90 percent leaves 5 percent in each tail. σ is treated as known, so the standard normal distribution gives the critical value. Margin of error. Interval: estimate plus or minus margin.
The answer. So the answer is 90 percent CI: (48.3551, 51.6449); margin of error 1.64485. We are 90 percent confident that the population mean μ lies between 48.3551 and 51.6449. The confidence describes the method: about 90 percent of intervals built this way from repeated samples would capture the true value.
Check. The interval is centred on the estimate: (48.3551 plus 51.6449) / 2 equals 50.
About confidence intervals
Build confidence intervals for a mean or a proportion.
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