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Balancing chemical equationsChemistryHigh schoolabout 1:27

Balance the chemical equation KMnO4 + HCl → KCl + MnCl2 + H2O + Cl2: animated lesson

A narrated, step-by-step balancing chemical equations video lesson with captions. Final answer: 2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.5 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Worked example
    Balance the chemical equation KMnO4 + HCl → KCl + MnCl2 + H2O + Cl2.
  2. 2. Step by step
    1. K:1c1=1c3Mn:1c1=1c4O:4c1=1c5H:1c2=2c5Cl:1c2=1c3+2c4+2c6\text{K}: 1c_{1} = 1c_{3} \\ \text{Mn}: 1c_{1} = 1c_{4} \\ \text{O}: 4c_{1} = 1c_{5} \\ \text{H}: 1c_{2} = 2c_{5} \\ \text{Cl}: 1c_{2} = 1c_{3} + 2c_{4} + 2c_{6}
      Write an atom balance for each element
    2. c1=2, c2=16, c3=2, c4=2, c5=8, c6=5c_{1} = 2,\ c_{2} = 16,\ c_{3} = 2,\ c_{4} = 2,\ c_{5} = 8,\ c_{6} = 5
      Solve the linear system with the smallest whole numbers
    3. 2KMnO4+16HCl→2KCl+2MnCl2+8H2O+5Cl22\mathrm{KMnO_{4}} + 16\mathrm{HCl} \rightarrow 2\mathrm{KCl} + 2\mathrm{MnCl_{2}} + 8\mathrm{H_{2}O} + 5\mathrm{Cl_{2}}
      Balanced equation
  3. 3. The answer
    2KMnO4+16HCl→2KCl+2MnCl2+8H2O+5Cl22\mathrm{KMnO_{4}} + 16\mathrm{HCl} \rightarrow 2\mathrm{KCl} + 2\mathrm{MnCl_{2}} + 8\mathrm{H_{2}O} + 5\mathrm{Cl_{2}}

    2KMnO4 + 16HCl → 2KCl + 2MnCl2 + 8H2O + 5Cl2

  4. 4. Check
    • K: 2 = 2, Mn: 2 = 2, O: 8 = 8, H: 16 = 16, Cl: 16 = 16 ✓

Transcript

The problem. Here is the problem: Balance the chemical equation KMnO4 plus HCl → KCl plus MnCl2 plus H2O plus Cl2. Balance atoms of every element, then use the coefficients as mole ratios.

Step by step. Write an atom balance for each element. Give each species an unknown coefficient; atoms of every element must be equal on both sides. Solve the linear system with the smallest whole numbers. Exact elimination leaves one free coefficient; scaling by the least common denominator gives integers. Balanced equation.

The answer. So the answer is 2KMnO4 plus 16HCl → 2KCl plus 2MnCl2 plus 8H2O plus 5Cl2. Coefficients in a balanced equation count particles (moles), not grams. Convert grams to moles, apply the mole ratio, then convert back to grams with the other species prime molar mass. Assumes the reaction goes to completion with the known species fully consumed (or formed).

Check. K: 2 equals 2, Mn: 2 equals 2, O: 8 equals 8, H: 16 equals 16, Cl: 16 equals 16, which checks out.

About balancing chemical equations

Balance chemical equations so every element has the same number of atoms on both sides.

Balance the chemical equation KMnO4 + HCl → KCl + MnCl2 +…