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Definite integralsCalculusCollegeabout 0:53

Definite integral of ln(x) from 1 to 2: animated lesson

A narrated, step-by-step definite integrals video lesson with captions. Final answer: 0.3862943611.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.3 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Evaluating an integral
    ∫12ln⁡(x) dx\int_{1}^{2} \ln\left( x\right)\,dx
  2. 2. Step by step
    1. ∫12ln⁡(x) dx\int_{1}^{2} \ln\left( x\right)\,dx
      Start with the definite integral
    2. ∫ln⁡(x) dx=x(ln⁡(x)−1)\int \ln\left( x\right)\,dx = x \left(\ln\left( x\right)-1\right)
      ∫ ln x dx = x ln x − x (integration by parts)
    3. F(x)=x(ln⁡(x)−1)F(x) = x \left(\ln\left( x\right)-1\right)
      Antiderivative
    4. F(2)−F(1)=−0.6137056389−(−1)=0.3862943611F(2) - F(1) = -0.6137056389 - \left(-1\right) = 0.3862943611
      Apply the fundamental theorem of calculus
  3. 3. The answer
    ∫12ln⁡(x) dx=0.3862943611\int_{1}^{2} \ln\left( x\right)\,dx = 0.3862943611

    ∫ from 1 to 2 = 0.3862943611

  4. 4. Check
    • Differentiated the antiderivative and compared it with the integrand ✓
    • Adaptive Simpson's rule gives 0.3862943611 ✓

Transcript

The problem. Here is the problem: integral of ln(x) from 1 to 2. Evaluate the definite integral of ln(x) from x equals 1 to x equals 2.

Step by step. Start with the definite integral. the integral of ln x dx equals x ln x minus x (integration by parts). Antiderivative. Apply the fundamental theorem of calculus.

The answer. So the answer is 0.3862943611. A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.

Check. Differentiated the antiderivative and compared it with the integrand, which checks out. Adaptive Simpson prime s rule gives 0.3862943611, which checks out.

About definite integrals

Evaluate definite integrals with the fundamental theorem of calculus.

Definite integral of ln(x) from 1 to 2: Step-by-Step Lesson