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Definite integralsCalculusCollegeabout 0:56

Definite integral of sin(x)^2 from 0 to 2pi: animated lesson

A narrated, step-by-step definite integrals video lesson with captions. Final answer: 3.141592654 = π.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Evaluating an integral
    ∫02πsin⁡(x)2 dx\int_{0}^{2\pi} {\sin\left( x\right)}^{2}\,dx
  2. 2. Step by step
    1. ∫02πsin⁡(x)2 dx\int_{0}^{2\pi} {\sin\left( x\right)}^{2}\,dx
      Start with the definite integral
    2. ∫sin⁡(x)2 dx=x2−sin⁡(2x)4\int {\sin\left( x\right)}^{2}\,dx = \frac{x}{2}-\frac{\sin\left(2x\right)}{4}
      Power-reducing identity: sin² u = (1 − cos 2u)/2
    3. F(x)=x2−sin⁡(2x)4F(x) = \frac{x}{2}-\frac{\sin\left(2x\right)}{4}
      Antiderivative
    4. F(2π)−F(0)=3.141592654−0=3.141592654F(2\pi) - F(0) = 3.141592654 - 0 = 3.141592654
      Apply the fundamental theorem of calculus
  3. 3. The answer
    ∫02πsin⁡(x)2 dx=3.141592654\int_{0}^{2\pi} {\sin\left( x\right)}^{2}\,dx = 3.141592654

    ∫ from 0 to 2π = 3.141592654 = π

  4. 4. Check
    • Differentiated the antiderivative and compared it with the integrand ✓
    • Adaptive Simpson's rule gives 3.141592654 ✓

Transcript

The problem. Here is the problem: integral of sin(x) squared from 0 to 2pi. Evaluate the definite integral of sin(x) squared from x equals 0 to x equals 2pi.

Step by step. Start with the definite integral. Power-reducing identity: sin squared u equals (1 minus cos 2u)/2. Antiderivative. Apply the fundamental theorem of calculus.

The answer. So the answer is 3.141592654 equals pi. A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.

Check. Differentiated the antiderivative and compared it with the integrand, which checks out. Adaptive Simpson prime s rule gives 3.141592654, which checks out.

About definite integrals

Evaluate definite integrals with the fundamental theorem of calculus.

Definite integral of sin(x)^2 from 0 to 2pi: Animated Lesson