Definite integral of sin(x)^2 from 0 to 2pi: animated lesson
A narrated, step-by-step definite integrals video lesson with captions. Final answer: 3.141592654 = π.
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemEvaluating an integral
- 2. Step by step
- Start with the definite integral
- Power-reducing identity: sin² u = (1 − cos 2u)/2
- Antiderivative
- Apply the fundamental theorem of calculus
- 3. The answer
∫ from 0 to 2π = 3.141592654 = π
- 4. Check
- Differentiated the antiderivative and compared it with the integrand ✓
- Adaptive Simpson's rule gives 3.141592654 ✓
Transcript
The problem. Here is the problem: integral of sin(x) squared from 0 to 2pi. Evaluate the definite integral of sin(x) squared from x equals 0 to x equals 2pi.
Step by step. Start with the definite integral. Power-reducing identity: sin squared u equals (1 minus cos 2u)/2. Antiderivative. Apply the fundamental theorem of calculus.
The answer. So the answer is 3.141592654 equals pi. A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.
Check. Differentiated the antiderivative and compared it with the integrand, which checks out. Adaptive Simpson prime s rule gives 3.141592654, which checks out.
About definite integrals
Evaluate definite integrals with the fundamental theorem of calculus.
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