Evaluate the sum of 1/sqrt(n) from n=1 to infinity: animated lesson
A narrated, step-by-step sequences and series video lesson with captions. Final answer: The series diverges (comparison with Σ 1/n).
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.7 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked example
- 2. Step by step
- Write the series
- nth-term test
- Limit comparison with a p-series
- 3. The answer
comparison with Σ 1/n ⇒ diverges
- 4. Check
- Partial sums (supporting evidence, not a proof): S₁₀ = 5.0209979, S₁₀₀ = 18.589604, S₁₀₀₀ = 61.801009, S₁₀₀₀₀ = 198.54465
Transcript
The problem. Here is the problem: Σ 1 / sqrt(n), n equals 1 to ∞. Decide whether Σ 1 / sqrt(n) (n from 1 to ∞) converges or diverges.
Step by step. Write the series. Σ a(n) for n equals 1, 2, 3, … with a(n) equals 1 / sqrt(n). First terms: 1, 0.707107, 0.57735, 0.5, …. nth-term test. lim a(n) equals 0, so the divergence test is inconclusive; the terms do shrink, so a finer test is needed. Limit comparison with a p-series. Positive terms: compare instead with Σ 1/n: lim a(n) times n equals ∞. The limit is ∞, so eventually the terms are larger than 1/n; that p-series diverges (p less than or equal to 1), so this one does too.
The answer. So the answer is The series diverges (comparison with Σ 1/n). A series converges when its partial sums approach a finite number. The terms must tend to 0 for that to happen, but that alone is not enough (the harmonic series diverges), so a comparison, ratio, root, alternating or integral test is used to decide.
Check. Partial sums (supporting evidence, not a proof): S₁₀ equals 5.0209979, S₁₀₀ equals 18.589604, S₁₀₀₀ equals 61.801009, S₁₀₀₀₀ equals 198.54465.
About sequences and series
Evaluate finite sums and arithmetic and geometric series.
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