Factor x^3 + 27: animated lesson
A narrated, step-by-step expanding and factoring video lesson with captions. Final answer: (x + 3)(x^2 - 3x + 9).
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked example
- 2. Steps, part 1
- Write the polynomial in standard form
- Recognise a special pattern
- Apply the Rational Root Theorem
- Divide by (x + 3) using synthetic division at x = -3
- 3. Steps, part 2
- Check the remaining quadratic
- Write the complete factorization
- 4. The answer
x^3 + 27 = (x + 3)(x^2 - 3x + 9)
- 5. Check
- Expanding (x + 3)(x^2 - 3x + 9) gives back x^3 + 27.
Transcript
The problem. Here is the problem: x cubed plus 27. Factor a polynomial over the rational numbers.
Steps, part 1. Write the polynomial in standard form. Recognise a special pattern. The remaining factor is a sum of cubes: a cubed plus b cubed equals (a plus b)(a squared minus ab plus b squared). Apply the Rational Root Theorem. Any rational root p/q has p dividing the constant term 27 and q dividing the leading coefficient 1. Testing these candidates gives the root negative 3. Divide by (x plus 3) using synthetic division at x equals negative 3.
Steps, part 2. Check the remaining quadratic. Its discriminant is negative 27, negative, so it is irreducible over the rationals. Write the complete factorization.
The answer. So the answer is (x plus 3)(x squared minus 3x plus 9). x cubed plus 27 factors completely over the rationals as (x plus 3)(x squared minus 3x plus 9).
Check. Expanding (x plus 3)(x squared minus 3x plus 9) gives back x cubed plus 27.
About expanding and factoring
Expand products of brackets and factor polynomials completely.
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