Find all three angles of a triangle with sides 3, 4 and 5: animated lesson
A narrated, step-by-step triangles video lesson with captions. Final answer: A ≈ 36.869898°, B ≈ 53.130102°, C ≈ 90°.
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.6 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked exampleFind all three angles of a triangle with sides 3, 4 and 5.
- 2. Steps, part 1
- Check the triangle inequality
- Angle C (opposite side c)
- Angle A (opposite side a)
- Third angle from the angle sum
- 3. Steps, part 2
- Area from two sides and the included angle
- 4. The answer
A ≈ 36.869898°, B ≈ 53.130102°, C ≈ 90°
- 5. Check
- A + B + C = 180°.
- Heron's formula gives the same area: 6.
- Law of sines ratios: a/sin A ≈ 5, b/sin B ≈ 5, c/sin C ≈ 5.
Transcript
The problem. Here is the problem: Find all three angles of a triangle with sides 3, 4 and 5. SSS: find all three angles.
Steps, part 1. Check the triangle inequality. 3 plus 4 equals 7 greater than 5, so a triangle exists. Angle C (opposite side c). Angle A (opposite side a). Third angle from the angle sum.
Steps, part 2. Area from two sides and the included angle.
The answer. So the answer is A approximately 36.869898°, B approximately 53.130102°, C approximately 90°. The triangle has sides a equals 3, b equals 4, c equals 5 and angles A approximately 36.869898°, B approximately 53.130102°, C approximately 90°. It is a right scalene triangle with area approximately 6 and perimeter approximately 12.
Check. A plus B plus C equals 180°. Heron prime s formula gives the same area: 6. Law of sines ratios: a/sin A approximately 5, b/sin B approximately 5, c/sin C approximately 5.
About triangles
Solve triangles with the law of sines and the law of cosines, and find their area.
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