Find arctan(-1) and every angle in [0°, 360°) with tan x = -1: animated lesson
A narrated, step-by-step trigonometric equations video lesson with captions. Final answer: arctan(-1) = -45° (-π/4); solutions in [0°, 360°): 135°, 315°; general: x = -45° + 180°n.
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Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.6 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked exampleFind arctan(-1) and every angle in [0°, 360°) with tan x = -1.
- 2. Step by step
- Principal value of arctan, taken in the range (−π/2, π/2)
- tan repeats every 180°, so add multiples of 180°
- Solutions in one full turn, 0° ≤ x < 360°
- General solution, n any integer
- 3. The answer
arctan(-1) = -45°
- 4. Check
- Substituting each solution back: tan(135°) ≈ -1; tan(315°) ≈ -1.
Transcript
The problem. Here is the problem: Find arctan(negative 1) and every angle in [0°, 360°) with tan x equals negative 1. Find the angle whose tan is negative 1: the principal value of arctan, every solution of tan(x) equals negative 1 in one turn, and the general solution.
Step by step. Principal value of arctan, taken in the range (−pi/2, pi/2). negative 45° is a special angle, so the answer is exact. tan repeats every 180°, so add multiples of 180°. Solutions in one full turn, 0° less than or equal to x less than 360°. General solution, n any integer.
The answer. So the answer is arctan(negative 1) equals negative 45° (-pi/4); solutions in [0°, 360°): 135°, 315°; general: x equals negative 45° plus 180°n. An inverse trigonometric function returns one angle, the principal value. Because the trigonometric functions repeat, the equation tan(x) equals negative 1 has infinitely many solutions; the calculator lists those in one turn and the general pattern.
Check. Substituting each solution back: tan(135°) approximately negative 1; tan(315°) approximately negative 1.
About trigonometric equations
Solve trigonometric equations and give every solution.
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