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Work, energy and powerPhysicsHigh schoolabout 0:42

Find the kinetic energy of a 0.06 kg object moving at 300 m/s: animated lesson

A narrated, step-by-step work, energy and power video lesson with captions. Final answer: kinetic energy KE = 2700 J.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.3 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Worked example
    Find the kinetic energy of a 0.06 kg object moving at 300 m/s.
  2. 2. Step by step
    1. KE=12mv2KE = \tfrac12mv^2
      Formula: kinetic energy
    2. KE=12 (0.06 kg)⋅(300 m/s)2=2700 JKE = \tfrac12\,(0.06\ \text{kg})\cdot (300\ \text{m/s})^2 = 2700\ \text{J}
      Substitute the known values
  3. 3. The answer
    kinetic energy KE = 2700 J\text{kinetic energy KE = 2700 J}

    kinetic energy KE = 2700 J

  4. 4. Check
    • Substituted every value back into the formula: both sides agree ✓

Transcript

The problem. Here is the problem: Find the kinetic energy of a 0.06 kg object moving at 300 m/s. Use the kinetic energy formula, rearranged for the unknown, in SI units.

Step by step. Formula: kinetic energy. Substitute the known values.

The answer. So the answer is kinetic energy KE equals 2700 J. Kinetic energy grows with the square of speed: doubling v multiplies KE by four. It is never negative, and the speed found from KE is a magnitude.

Check. Substituted every value back into the formula: both sides agree, which checks out.

About work, energy and power

Work done by a force, kinetic and potential energy, and power.

Find the kinetic energy of a 0.06 kg object moving at 300…