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StoichiometryChemistryHigh schoolabout 1:34

Grams of Fe from 80 g of Fe2O3: animated lesson

A narrated, step-by-step stoichiometry video lesson with captions. Final answer: Fe2O3 + 3CO → 2Fe + 3CO2; 80 g Fe2O3 → Fe: 55.9545 g (1.00196 mol).

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Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.6 MB) · Captions (WebVTT)

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1. The problem
Worked example
In the reaction Fe2O3 + CO → Fe + CO2, how many grams of Fe form from 80 g of Fe2O3?
2. Steps, part 1
1. $\text{Fe}: 2c_{1} = 1c_{3} \\ \text{O}: 3c_{1} + 1c_{2} = 2c_{4} \\ \text{C}: 1c_{2} = 1c_{4}$
  Write an atom balance for each element
2. $c_{1} = 1,\ c_{2} = 3,\ c_{3} = 2,\ c_{4} = 3$
  Solve the linear system with the smallest whole numbers
3. $\mathrm{Fe_{2}O_{3}} + 3\mathrm{CO} \rightarrow 2\mathrm{Fe} + 3\mathrm{CO_{2}}$
  Balanced equation
4. $n = \frac{80\ \text{g}}{159.687\ \text{g/mol}} = 0.50098\ \text{mol}$
  Moles of Fe2O3
3. Steps, part 2
1. $n = 0.50098 \times \frac{2}{1} = 1.00196\ \text{mol},\quad m = 1.00196 \times 55.845 = 55.9545\ \text{g}$
  Fe via the mole ratio 2 : 1
4. The answer
$\mathrm{Fe_{2}O_{3}} + 3\mathrm{CO} \rightarrow 2\mathrm{Fe} + 3\mathrm{CO_{2}}$
Fe2O3 + 3CO → 2Fe + 3CO2
5. Check
- Fe: 2 = 2, O: 6 = 6, C: 3 = 3 ✓
- Fe is produced in a 2 : 1 mole ratio to Fe2O3.

Transcript

The problem. Here is the problem: In the reaction Fe2O3 plus CO → Fe plus CO2, how many grams of Fe form from 80 g of Fe2O3? Balance atoms of every element, then use the coefficients as mole ratios.

Steps, part 1. Write an atom balance for each element. Give each species an unknown coefficient; atoms of every element must be equal on both sides. Solve the linear system with the smallest whole numbers. Exact elimination leaves one free coefficient; scaling by the least common denominator gives integers. Balanced equation. Moles of Fe2O3.

Steps, part 2. Fe via the mole ratio 2: 1.

The answer. So the answer is Fe2O3 plus 3CO → 2Fe plus 3CO2; 80 g Fe2O3 → Fe: 55.9545 g (1.00196 mol). Coefficients in a balanced equation count particles (moles), not grams. Convert grams to moles, apply the mole ratio, then convert back to grams with the other species prime molar mass. Assumes the reaction goes to completion with the known species fully consumed (or formed).

Check. Fe: 2 equals 2, O: 6 equals 6, C: 3 equals 3, which checks out. Fe is produced in a 2: 1 mole ratio to Fe2O3.

About stoichiometry

Use a balanced equation to find how many grams of product form from a given mass of reactant.

Grams of Fe from 80 g of Fe2O3: Animated Step-by-Step Lesson