How much 18 M stock solution do you need to make 100 mL of 2 M solution?: animated lesson
A narrated, step-by-step solutions and concentration video lesson with captions. Final answer: initial volume V₁ = 11.1111 mL; add 88.8889 mL of solvent.
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked exampleHow much 18 M stock solution do you need to make 100 mL of 2 M solution?
- 2. Step by step
- Moles of solute stay the same when you dilute
- Rearrange for initial volume V₁
- Substitute
- Solvent to add
- 3. The answer
initial volume V₁ = 11.1111 mL
- 4. Check
- M₁V₁ = 200 and M₂V₂ = 200 ✓
Transcript
The problem. Here is the problem: How much 18 M stock solution do you need to make 100 mL of 2 M solution? Diluting adds solvent but not solute, so the moles of solute before and after are equal.
Step by step. Moles of solute stay the same when you dilute. Rearrange for initial volume V₁. Substitute. Solvent to add. Start with V₁ of the stock and add solvent up to V₂.
The answer. So the answer is initial volume V₁ equals 11.1111 mL; add 88.8889 mL of solvent. Any volume unit works in M₁V₁ equals M₂V₂ as long as both volumes use the same one. Moles of solute: 0.2 mol.
Check. M₁V₁ equals 200 and M₂V₂ equals 200, which checks out.
About solutions and concentration
Molarity, dilution and moles of solute in a solution.
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