Independent events have P(A) = 0.5 and P(B) = 1/3. Find P(A and B) and P(A or B): animated lesson
A narrated, step-by-step probability video lesson with captions. Final answer: P(A and B) = 1/6 ≈ 0.16666667; P(A or B) = 2/3 ≈ 0.66666667; P(neither) = 1/3 ≈ 0.33333333.
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked exampleIndependent events have P(A) = 0.5 and P(B) = 1/3. Find P(A and B) and P(A or B).
- 2. Step by step
- Both: multiply, because the events are independent
- At least one: add and subtract the overlap
- Exactly one of them
- Neither
- 3. The answer
P(A and B) = 1/6 ≈ 0.16666667; P(A or B) = 2/3 ≈ 0.66666667; P(neither) = 1/3 ≈ 0.33333333
- 4. Check
- P(A or B) + P(neither) = 1 = 1.
Transcript
The problem. Here is the problem: Independent events have P(A) equals 0.5 and P(B) equals 1 over 3. Find P(A and B) and P(A or B). Two independent events A and B.
Step by step. Both: multiply, because the events are independent. At least one: add and subtract the overlap. Exactly one of them. Neither.
The answer. So the answer is P(A and B) equals 1 over 6 approximately 0.16666667; P(A or B) equals 2 over 3 approximately 0.66666667; P(neither) equals 1 over 3 approximately 0.33333333. For independent events the probability that both happen is the product of the individual probabilities.
Check. P(A or B) plus P(neither) equals 1 equals 1.
About probability
Probability of single events, complements, independent events and binomial outcomes.
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