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Definite integralsCalculusCollegeabout 0:48

Integrate |x - 1| from 0 to 3: animated lesson

A narrated, step-by-step definite integrals video lesson with captions. Final answer: 5/2 ≈ 2.5.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.3 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Evaluating an integral
    ∫03∣x−1∣ dx\int_{0}^{3} \left| x-1\right|\,dx
  2. 2. Step by step
    1. ∫03∣x−1∣ dx\int_{0}^{3} \left| x-1\right|\,dx
      Start with the definite integral
    2. ∫∣x−1∣ dx=(x−1)⋅∣x−1∣2\int \left| x-1\right|\,dx = \frac{\left( x-1\right)\cdot\left| x-1\right|}{2}
      ∫ |u| du = u|u|/2
    3. F(x)=(x−1)⋅∣x−1∣2F(x) = \frac{\left( x-1\right)\cdot\left| x-1\right|}{2}
      Antiderivative
    4. F(3)−F(0)=2−(−0.5)=52≈2.5F(3) - F(0) = 2 - \left(-0.5\right) = \frac{5}{2} \approx 2.5
      Apply the fundamental theorem of calculus
  3. 3. The answer
    ∫03∣x−1∣ dx=52≈2.5\int_{0}^{3} \left| x-1\right|\,dx = \frac{5}{2} \approx 2.5

    ∫ from 0 to 3 = 5/2 ≈ 2.5

  4. 4. Check
    • Differentiated the antiderivative and compared it with the integrand ✓
    • Adaptive Simpson's rule gives 2.5 ✓

Transcript

The problem. Here is the problem: integrate |x minus 1| from 0 to 3. Evaluate the definite integral of abs(x minus 1) from x equals 0 to x equals 3.

Step by step. Start with the definite integral. the integral of |u| du equals u|u|/2. Antiderivative. Apply the fundamental theorem of calculus.

The answer. So the answer is 5 over 2 approximately 2.5. A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.

Check. Differentiated the antiderivative and compared it with the integrand, which checks out. Adaptive Simpson prime s rule gives 2.5, which checks out.

About definite integrals

Evaluate definite integrals with the fundamental theorem of calculus.

Integrate |x - 1| from 0 to 3: Animated Step-by-Step Lesson