Skip to content
  • Open the math solver
  • Ask the AI tutor
  • Find an AP course
  • Create a quiz
  • Open the calculator
  • Graphing Calculator
  • Browse all calculators
  • Read math guides
↑ ↓Enter to open · Esc to close
Solve a problem
Electric circuitsPhysicsHigh schoolabout 0:53

Resistors of 100, 220 Ω are connected in series to a 9 V battery. Find the total resistance and current: animated lesson

A narrated, step-by-step electric circuits video lesson with captions. Final answer: R_T = 320 Ω; I = 0.028125 A, P = 0.253125 W.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Worked example
    Resistors of 100, 220 Ω are connected in series to a 9 V battery. Find the total resistance and current.
  2. 2. Step by step
    1. RT=100+220=320 ΩR_T = 100 + 220 = 320\ \Omega
      Series: resistances add
    2. I=VRT=9320=0.028125 AI = \frac{V}{R_T} = \frac{9}{320} = 0.028125\ \text{A}
      Total current from Ohm's law
    3. V1=2.8125 V, V2=6.1875 VV_{1} = 2.8125\ \text{V},\ V_{2} = 6.1875\ \text{V}
      Voltage across each resistor (same current)
    4. P=VI=0.253125 WP = VI = 0.253125\ \text{W}
      Power delivered
  3. 3. The answer
    R_T = 320 Ω; I = 0.028125 A, P = 0.253125 W\text{R\_T = 320 Ω; I = 0.028125 A, P = 0.253125 W}

    R_T = 320 Ω; I = 0.028125 A, P = 0.253125 W

  4. 4. Check
    • R_T ≥ every individual resistor ✓

Transcript

The problem. Here is the problem: Resistors of 100, 220 Ω are connected in series to a 9 V battery. Find the total resistance and current. Resistors in series carry the same current; their resistances add.

Step by step. Series: resistances add. Total current from Ohm prime s law. Voltage across each resistor (same current). The drops add up to the supply voltage. Power delivered.

The answer. So the answer is R T equals 320 Ω; I equals 0.028125 A, P equals 0.253125 W. The equivalent resistance of a series chain is always larger than its largest resistor.

Check. R T greater than or equal to every individual resistor, which checks out.

About electric circuits

Ohm's law, electrical power and resistors in series and parallel.

Resistors of 100, 220 Ω are connected in series to a 9 V…