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CalculusCalculus 1College

Limits and Continuity

Evaluate limits algebraically and decide continuity.

A limit describes the value a function approaches as its input approaches some number, whether or not the function is defined there. Writing lim⁡x→af(x)=L\lim_{x \to a} f(x) = L means f(x)f(x) can be made as close to LL as you like by taking xx close enough to aa, from both sides.

Limits are the foundation of calculus: derivatives are limits of difference quotients and integrals are limits of sums. The practical toolkit is short: try direct substitution, and if that gives the indeterminate form 00\frac{0}{0}, simplify by factoring, rationalising or using a known limit, then substitute again.

Key terms

Limit
The value f(x) approaches as x approaches a.
lim⁡x→af(x)=L\lim_{x\to a} f(x) = L

Key ideas

  • If ff is continuous at aa, the limit is simply f(a)f(a).
  • A two-sided limit exists only if the left and right limits agree.
  • lim⁡x→0sin⁡xx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 with xx in radians.
  • For rational functions at infinity, compare the degrees of numerator and denominator.

Worked example

Evaluate lim⁡x→3x2−9x−3\lim_{x \to 3} \frac{x^2 - 9}{x - 3}.

  1. Substitution gives 00\frac{0}{0}, so simplify.
  2. Factor: (x−3)(x+3)x−3\frac{(x - 3)(x + 3)}{x - 3}.
  3. Cancel for x≠3x \ne 3: x+3x + 3.
  4. Substitute: 3+3=63 + 3 = 6.

Answer: 66

Common mistakes

  • Declaring a 00\frac{0}{0} limit to be 0 or undefined without simplifying.
  • Assuming the limit equals the function value at a hole.
  • Checking only one side for piecewise functions.

Practice questions

Try each one, then open the answer. Numerical answers on this page are verified by an automated calculation check.

  1. 1.Evaluate lim⁡x→2(3x2−1)\lim_{x \to 2} (3x^2 - 1).

    Show answer

    1111

  2. 2.Evaluate lim⁡x→∞4x2+12x2−5\lim_{x \to \infty} \frac{4x^2 + 1}{2x^2 - 5}.

    Show answer

    22

  3. 3.Evaluate lim⁡x→1x2+x−2x−1\lim_{x \to 1} \frac{x^2 + x - 2}{x - 1}.

    Show answer

    33

Keep practising

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