A 2 kg object moving at 3 m/s collides and sticks to a 1 kg object moving at 0 m/s. What is their common velocity?: animated lesson
A narrated, step-by-step momentum and collisions video lesson with captions. Final answer: v = 2 m/s (perfectly inelastic; 3 J of kinetic energy lost, 33.33%).
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked exampleA 2 kg object moving at 3 m/s collides and sticks to a 1 kg object moving at 0 m/s. What is their common velocity?
- 2. Step by step
- Total momentum before
- Perfectly inelastic: the objects move together
- Kinetic energy before and after
- 3. The answer
v = 2 m/s (perfectly inelastic; 3 J of kinetic energy lost, 33.33%)
- 4. Check
- Momentum before 6 = after 6 kg·m/s ✓
Transcript
The problem. Here is the problem: A 2 kg object moving at 3 m/s collides and sticks to a 1 kg object moving at 0 m/s. What is their common velocity? One-dimensional collision; positive velocities point one way, negative the other.
Step by step. Total momentum before. Perfectly inelastic: the objects move together. Kinetic energy before and after.
The answer. So the answer is v equals 2 m/s (perfectly inelastic; 3 J of kinetic energy lost, 33.33 percent). Momentum is conserved in every collision when no external force acts. Kinetic energy is conserved only in elastic collisions; in a perfectly inelastic collision the objects stick together and the maximum possible kinetic energy is converted to heat, sound and deformation.
Check. Momentum before 6 equals after 6 kg times m/s, which checks out.
About momentum and collisions
Momentum, impulse and conservation of momentum in collisions.
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