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Momentum and collisionsPhysicsHigh schoolabout 1:01

A 0.5 kg object moving at 6 m/s collides and sticks to a 1.5 kg object moving at 0 m/s. What is their common velocity?: animated lesson

A narrated, step-by-step momentum and collisions video lesson with captions. Final answer: v = 1.5 m/s (perfectly inelastic; 6.75 J of kinetic energy lost, 75%).

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Worked example
    A 0.5 kg object moving at 6 m/s collides and sticks to a 1.5 kg object moving at 0 m/s. What is their common velocity?
  2. 2. Step by step
    1. p=m1u1+m2u2=0.5(6)+1.5(0)=3 kg⋅m/sp = m_1u_1 + m_2u_2 = 0.5(6) + 1.5(0) = 3\ \text{kg·m/s}
      Total momentum before
    2. v=m1u1+m2u2m1+m2=32=1.5 m/sv = \frac{m_1u_1 + m_2u_2}{m_1+m_2} = \frac{3}{2} = 1.5\ \text{m/s}
      Perfectly inelastic: the objects move together
    3. KEi=9 J,KEf=2.25 J,ΔKE=−6.75 JKE_i = 9\ \text{J},\quad KE_f = 2.25\ \text{J},\quad \Delta KE = -6.75\ \text{J}
      Kinetic energy before and after
  3. 3. The answer
    v = 1.5 m/s (perfectly inelastic; 6.75 J of kinetic energy lost, 75%)\text{v = 1.5 m/s (perfectly inelastic; 6.75 J of kinetic energy lost, 75\%)}

    v = 1.5 m/s (perfectly inelastic; 6.75 J of kinetic energy lost, 75%)

  4. 4. Check
    • Momentum before 3 = after 3 kg·m/s ✓

Transcript

The problem. Here is the problem: A 0.5 kg object moving at 6 m/s collides and sticks to a 1.5 kg object moving at 0 m/s. What is their common velocity? One-dimensional collision; positive velocities point one way, negative the other.

Step by step. Total momentum before. Perfectly inelastic: the objects move together. Kinetic energy before and after.

The answer. So the answer is v equals 1.5 m/s (perfectly inelastic; 6.75 J of kinetic energy lost, 75 percent). Momentum is conserved in every collision when no external force acts. Kinetic energy is conserved only in elastic collisions; in a perfectly inelastic collision the objects stick together and the maximum possible kinetic energy is converted to heat, sound and deformation.

Check. Momentum before 3 equals after 3 kg times m/s, which checks out.

About momentum and collisions

Momentum, impulse and conservation of momentum in collisions.

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