Skip to content
  • Open the math solver
  • Ask the AI tutor
  • Find an AP course
  • Create a quiz
  • Open the calculator
  • Graphing Calculator
  • Browse all calculators
  • Read math guides
↑ ↓Enter to open · Esc to close
Solve a problem
Momentum and collisionsPhysicsHigh schoolabout 1:00

A 60 kg object moving at 5 m/s collides and sticks to a 40 kg object moving at 0 m/s. What is their common velocity?: animated lesson

A narrated, step-by-step momentum and collisions video lesson with captions. Final answer: v = 3 m/s (perfectly inelastic; 300 J of kinetic energy lost, 40%).

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Worked example
    A 60 kg object moving at 5 m/s collides and sticks to a 40 kg object moving at 0 m/s. What is their common velocity?
  2. 2. Step by step
    1. p=m1u1+m2u2=60(5)+40(0)=300 kg⋅m/sp = m_1u_1 + m_2u_2 = 60(5) + 40(0) = 300\ \text{kg·m/s}
      Total momentum before
    2. v=m1u1+m2u2m1+m2=300100=3 m/sv = \frac{m_1u_1 + m_2u_2}{m_1+m_2} = \frac{300}{100} = 3\ \text{m/s}
      Perfectly inelastic: the objects move together
    3. KEi=750 J,KEf=450 J,ΔKE=−300 JKE_i = 750\ \text{J},\quad KE_f = 450\ \text{J},\quad \Delta KE = -300\ \text{J}
      Kinetic energy before and after
  3. 3. The answer
    v = 3 m/s (perfectly inelastic; 300 J of kinetic energy lost, 40%)\text{v = 3 m/s (perfectly inelastic; 300 J of kinetic energy lost, 40\%)}

    v = 3 m/s (perfectly inelastic; 300 J of kinetic energy lost, 40%)

  4. 4. Check
    • Momentum before 300 = after 300 kg·m/s ✓

Transcript

The problem. Here is the problem: A 60 kg object moving at 5 m/s collides and sticks to a 40 kg object moving at 0 m/s. What is their common velocity? One-dimensional collision; positive velocities point one way, negative the other.

Step by step. Total momentum before. Perfectly inelastic: the objects move together. Kinetic energy before and after.

The answer. So the answer is v equals 3 m/s (perfectly inelastic; 300 J of kinetic energy lost, 40 percent). Momentum is conserved in every collision when no external force acts. Kinetic energy is conserved only in elastic collisions; in a perfectly inelastic collision the objects stick together and the maximum possible kinetic energy is converted to heat, sound and deformation.

Check. Momentum before 300 equals after 300 kg times m/s, which checks out.

About momentum and collisions

Momentum, impulse and conservation of momentum in collisions.

A 60 kg object moving at 5 m/s collides and sticks to a 40…