Find the determinant of [[0,2,-4],[8,1,-6],[8,0,-8]]: animated lesson
A narrated, step-by-step matrices video lesson with captions. Final answer: det(A) = 64.
Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.
Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.3 MB) · Captions (WebVTT)
Steps on screen
- 1. The problemWorked example
- 2. Step by step
- Read the 3×3 matrix
- Expand along the first row (cofactor expansion)
- Evaluate each 2×2 minor
- Combine with the alternating signs + − +
- 3. The answer
det = 64
- 4. Check
- Computed exactly with fractions; row reduction gives the same value 64.
Transcript
The problem. Here is the problem: [[0, 2, negative 4], [8, 1, negative 6], [8, 0, negative 8]]. Find the determinant of a 3 times 3 matrix.
Step by step. Read the 3 times 3 matrix. Expand along the first row (cofactor expansion). Evaluate each 2 times 2 minor. Combine with the alternating signs plus minus +.
The answer. So the answer is det(A) equals 64. The determinant is 64, which is non-zero, so the matrix is invertible and its rows are linearly independent.
Check. Computed exactly with fractions; row reduction gives the same value 64.
About matrices
Determinants, inverses, products, transposes and eigenvalues of matrices.
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