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StoichiometryChemistryHigh schoolabout 1:29

Grams of NaCl from 46 g of Na: animated lesson

A narrated, step-by-step stoichiometry video lesson with captions. Final answer: 2Na + Cl2 → 2NaCl; 46 g Na → NaCl: 116.931 g (2.00087 mol).

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.6 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Worked example
    In the reaction Na + Cl2 → NaCl, how many grams of NaCl form from 46 g of Na?
  2. 2. Steps, part 1
    1. Na:1c1=1c3Cl:2c2=1c3\text{Na}: 1c_{1} = 1c_{3} \\ \text{Cl}: 2c_{2} = 1c_{3}
      Write an atom balance for each element
    2. c1=2, c2=1, c3=2c_{1} = 2,\ c_{2} = 1,\ c_{3} = 2
      Solve the linear system with the smallest whole numbers
    3. 2Na+Cl2→2NaCl2\mathrm{Na} + \mathrm{Cl_{2}} \rightarrow 2\mathrm{NaCl}
      Balanced equation
    4. n=46 g22.99 g/mol=2.00087 moln = \frac{46\ \text{g}}{22.99\ \text{g/mol}} = 2.00087\ \text{mol}
      Moles of Na
  3. 3. Steps, part 2
    1. n=2.00087×22=2.00087 mol,m=2.00087×58.44=116.931 gn = 2.00087 \times \frac{2}{2} = 2.00087\ \text{mol},\quad m = 2.00087 \times 58.44 = 116.931\ \text{g}
      NaCl via the mole ratio 2 : 2
  4. 4. The answer
    2Na+Cl2→2NaCl2\mathrm{Na} + \mathrm{Cl_{2}} \rightarrow 2\mathrm{NaCl}

    2Na + Cl2 → 2NaCl

  5. 5. Check
    • Na: 2 = 2, Cl: 2 = 2 ✓
    • NaCl is produced in a 2 : 2 mole ratio to Na.

Transcript

The problem. Here is the problem: In the reaction Na plus Cl2 → NaCl, how many grams of NaCl form from 46 g of Na? Balance atoms of every element, then use the coefficients as mole ratios.

Steps, part 1. Write an atom balance for each element. Give each species an unknown coefficient; atoms of every element must be equal on both sides. Solve the linear system with the smallest whole numbers. Exact elimination leaves one free coefficient; scaling by the least common denominator gives integers. Balanced equation. Moles of Na.

Steps, part 2. NaCl via the mole ratio 2: 2.

The answer. So the answer is 2Na plus Cl2 → 2NaCl; 46 g Na → NaCl: 116.931 g (2.00087 mol). Coefficients in a balanced equation count particles (moles), not grams. Convert grams to moles, apply the mole ratio, then convert back to grams with the other species prime molar mass. Assumes the reaction goes to completion with the known species fully consumed (or formed).

Check. Na: 2 equals 2, Cl: 2 equals 2, which checks out. NaCl is produced in a 2: 2 mole ratio to Na.

About stoichiometry

Use a balanced equation to find how many grams of product form from a given mass of reactant.

Grams of NaCl from 46 g of Na: Animated Step-by-Step Lesson