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Definite integralsCalculusCollegeabout 0:55

Integral of sqrt(x) from 0 to 4: animated lesson

A narrated, step-by-step definite integrals video lesson with captions. Final answer: 16/3 ≈ 5.3333333.

Video with a synthetic English voice and captions. Pick another language for subtitles in that language, or open the interactive version.

Video narrated by a synthetic voice (Piper TTS, en_US-ljspeech-high voice (LJ Speech dataset, public domain)); the steps come from our maths engine and the answer was checked independently. Download MP4 (0.4 MB) · Captions (WebVTT)

Steps on screen

  1. 1. The problem
    Evaluating an integral
    ∫04x dx\int_{0}^{4} \sqrt{x}\,dx
  2. 2. Step by step
    1. ∫04x dx\int_{0}^{4} \sqrt{x}\,dx
      Start with the definite integral
    2. ∫x dx=x32⋅23\int \sqrt{x}\,dx = \frac{{x}^{\frac{3}{2}}\cdot2}{3}
      ∫ √x dx = (2/3)x^(3/2)
    3. F(x)=x32⋅23F(x) = \frac{{x}^{\frac{3}{2}}\cdot2}{3}
      Antiderivative
    4. F(4)−F(0)=5.333333333−0=163≈5.3333333F(4) - F(0) = 5.333333333 - 0 = \frac{16}{3} \approx 5.3333333
      Apply the fundamental theorem of calculus
  3. 3. The answer
    ∫04x dx=163≈5.3333333\int_{0}^{4} \sqrt{x}\,dx = \frac{16}{3} \approx 5.3333333

    ∫ from 0 to 4 = 16/3 ≈ 5.3333333

  4. 4. Check
    • Differentiated the antiderivative and compared it with the integrand ✓
    • Adaptive Simpson's rule gives 5.333333333 ✓

Transcript

The problem. Here is the problem: integral of sqrt(x) from 0 to 4. Evaluate the definite integral of sqrt(x) from x equals 0 to x equals 4.

Step by step. Start with the definite integral. the integral of the square root of x dx equals (2 over 3)x to the power 3 over 2). Antiderivative. Apply the fundamental theorem of calculus.

The answer. So the answer is 16 over 3 approximately 5.3333333. A definite integral gives the signed area between the curve and the x-axis: area above the axis counts as positive and area below counts as negative.

Check. Differentiated the antiderivative and compared it with the integrand, which checks out. Adaptive Simpson prime s rule gives 5.333333333, which checks out.

About definite integrals

Evaluate definite integrals with the fundamental theorem of calculus.

Integral of sqrt(x) from 0 to 4: Definite integrals Lesson